How do you solve #(x-2)^2=25#?

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Answer 1 · 2016-09-12T16:48:06

#x = - 3, 7#

We have: #(x - 2)^(2) = 25#

First, let's take the square root of both sides of the equation:

#=> x - 2 = pm 5#

Then, let's add #2# to both sides:

#=> x = 2 pm 5#

#=> x = - 3, 7#

Therefore, the solutions to the equation are #x = - 3# and #x = 7#.