How do you solve #(x-2)^2=25#?

Question

15069 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-12T16:48:06

#x = - 3, 7#

We have: #(x - 2)^(2) = 25#

First, let's take the square root of both sides of the equation:

#=> x - 2 = pm 5#

Then, let's add #2# to both sides:

#=> x = 2 pm 5#

#=> x = - 3, 7#

Therefore, the solutions to the equation are #x = - 3# and #x = 7#.