How do you solve $(x-2)^2=25$ ?

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Answer 1 · 2016-09-12T16:48:06

$x = - 3, 7$

We have: $(x - 2)^(2) = 25$

First, let's take the square root of both sides of the equation:

$=> x - 2 = pm 5$

Then, let's add $2$ to both sides:

$=> x = 2 pm 5$

$=> x = - 3, 7$

Therefore, the solutions to the equation are $x = - 3$ and $x = 7$ .

How do you solve (x-2)^2=25(x-2)^2=25?