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How do you solve $x^{2} = 20$ $x^2=20$ ?

1 Answer

Jan 8, 2017

$x = \pm 2 \sqrt{5}$ $x=+-2sqrt(5)$

Explanation:

There are are two opposite solutions:

$x = \pm \sqrt{20}$ $x=+-sqrt(20)$

that's

$x = \pm 2 \sqrt{5}$ $x=+-2sqrt(5)$

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