How do you solve $x^{2} = 29$ $x^2=29$ ?

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How do you solve $x^{2} = 29$ $x^2=29$ ?

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Answer 1 · 2017-02-05T19:28:53

See the entire solution process below:

Explanation:

Take the square root of each side of the equation to solve for $x$ $x$ while keeping the equation balanced. The result of taking a square root will be plus and minus the solution:

$\sqrt{x^{2}} = \pm \sqrt{29}$ $sqrt(x^2) = +-sqrt(29)$

$x = \pm \sqrt{29} = \pm 5.358$ $x = +-sqrt(29) = +-5.358$ rounded to the nearest thousandth.

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How do you solve $x^{2} = 29$ $x^2=29$ ?

1 Answer

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How do you solve $x^{2} = 29$ $x^2=29$ ?