How do you solve $x^{2} - 2 = 17$ $x^2-2=17$ ?

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How do you solve $x^{2} - 2 = 17$ $x^2-2=17$ ?

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Answer 1 · 2017-02-17T14:18:23

See the entire solution process below:

Explanation:

First, add $2$ $color(red)(2)$ to each side of the equation to isolate $x^{2}$ $x^2$ while keeping the equation balanced:

$x^{2} - 2 + 2 = 17 + 2$ $x^2 - 2 + color(red)(2) = 17 + color(red)(2)$

$x^{2} - 0 = 19$ $x^2 - 0 = 19$

$x^{2} = 19$ $x^2 = 19$

Now, take the square root of each side of the equation to solve for $x$ $x$ while keeping the equation balanced. Also remember, the square root of a number has both a negative and positive answer:

$\sqrt{x^{2}} = \pm \sqrt{19}$ $sqrt(x^2) = +-sqrt(19)$

$x = \pm \sqrt{19} = \pm 4.359$ $x = +-sqrt(19) = +-4.359$ rounded to the nearest thousandth.

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How do you solve $x^{2} - 2 = 17$ $x^2-2=17$ ?

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