How do you solve sqrt(9-b)=sqrt(1-9b)9b=19b?

1 Answer
Jun 12, 2017

b = - 1b=1

Explanation:

We have: sqrt(9 - b) = sqrt(1 - 9 b)9b=19b

Let's square both sides of the equation:

Rightarrow (sqrt(9 - b))^(2) = (sqrt(1 - 9 b))^(2)(9b)2=(19b)2

Rightarrow 9 - b = 1 - 9 b9b=19b

Then, let's add 9 b9b to both sides:

Rightarrow 9 - b + 9 b = 1 - 9 b + 9 b9b+9b=19b+9b

Rightarrow 9 + 8 b = 19+8b=1

Now, let's subtract 99 from both sides:

Rightarrow 9 + 8 b - 8 = 1 - 99+8b8=19

Rightarrow 8 b = - 88b=8

Finally, to solve for bb, let's divide both sides by 88:

Rightarrow frac(8 b)(8) = - frac(8)(8)8b8=88

therefore b = - 1

Therefore, the solution to the equation is b = - 1.