How do you solve the equation #(3x-2/3)^2-2=5/2#?

1 Answer
Jim G.
Feb 21, 2018

#x=2/9+-sqrt2/2#

Explanation:

#"add 2 to both sides"#

#rArr(3x-2/3)^2=9/2#

#color(blue)"take square root of both sides"#

#sqrt((3x-2/3)^2)=+-sqrt(9/2)larrcolor(blue)"note plus or minus"#

#rArr3x-2/3=+-3/sqrt2=+-3/sqrt2xxsqrt2/sqrt2=(3sqrt2)/2#

#"add "2/3" to both sides"#

#rArr3x=2/3+-(3sqrt2)/2#

#"divide both sides by 3"#

#rArrx=2/9+-sqrt2/2larrcolor(red)"exact values"#

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