How do you solve $2 x^{2} + 5 = 19$ $2x^2+5=19$ ?

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How do you solve $2 x^{2} + 5 = 19$ $2x^2+5=19$ ?

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Answer 1 · 2018-04-14T12:10:37

x = $\pm \sqrt{7}$ $+-sqrt(7)$

Explanation:

1: $2 x^{2} + 5 = 19$ $2x^2 +5 = 19$
2: $2 x^{2} = 14$ $2x^2 = 14$
3: $x^{2} = 7$ $x^2 = 7$
4: Take a square root both side
5: x = $\pm \sqrt{7}$ $+-sqrt(7)$

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How do you solve $2 x^{2} + 5 = 19$ $2x^2+5=19$ ?

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How do you solve $2 x^{2} + 5 = 19$ $2x^2+5=19$ ?