How do you solve #4x^2-49=0# by taking square roots?
1 Answer
Apr 16, 2018
Explanation:
-
Add
#49# to both sides
#4x^2=49# -
Divide both sides by
#4#
#x^2= 49/4# -
Square root both sides
#x= +-sqrt(49/4)#
#x= +-7/2#