Question

What is the limit as x approaches infinity of `e^(-x^2)`?

Answer 1

`= 0`

Explanation:

as `x to oo => x^2 to oo => -x^2 to -oo`

As `x to oo => e^(-oo) = 1/e^oo = 1/ oo to 0`

`= 0`

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