Question

Question #6c63a

Answer 1

You are right. It is `132^@`.

Explanation:

As measure of arc `BFD=228^@`,

`m/_BPD=1/2m hat(BFD)=1/2xx228=114^@`

Now joining `BP` and `PD`, as `/_CBP=/_CDP=90^@`

`/_BCD=180^@-114^@=66^@`

and as `AE` subtends `/_AOE` at center, and ths is double `/_BCD`

`mhat(AFE)=2xx66^@=132^@`