Find the radius and center of the equation #x^2+y^2+6x-8y=0#? Precalculus Translation and Rotation of Axis Translation of a Conic Section 1 Answer VinÃcius Ferraz Jun 11, 2018 #S^1(P, r)# #P = (-3,4)# #r = 5# Explanation: #x^2 + 6x + 9# #+ y^2 - 8y + 16# # = 9 + 16# #(x +3)^2 + (y - 4)^2 = 25# Answer link Related questions How do you translate a graph to the left or right? How do you translate a graph up or down? What does it mean to translate a graph? If the equation of a conic section is #(x-3)^2/49+(y-4)^2/13=1#, how has its center been translated? If the equation of a conic section is #(x+6)^2/81-(y+1)^2/16=1#, how has its center been translated? If the equation of a conic section is #(x-2)^2+(y+5)^2=25#, how has its center been translated? What is the difference between the graph of #y=2x^2+3x-4# and the graph of #y=2(x-4)^2+3(x-4)-4#? Where is the center of the graph of #(x+3)^2+(y-2)^2=4#? How do use the method of translation of axes to sketch the curve #x^2+y^2-4x+3=0#? How do use the method of translation of axes to sketch the curve #x^2+y^2+2x-6y+6=0#? See all questions in Translation of a Conic Section Impact of this question 4117 views around the world You can reuse this answer Creative Commons License