# Find the radius and center of the equation x^2+y^2+6x-8y=0?

Jun 11, 2018

${S}^{1} \left(P , r\right)$
$P = \left(- 3 , 4\right)$
$r = 5$

#### Explanation:

${x}^{2} + 6 x + 9$
$+ {y}^{2} - 8 y + 16$
$= 9 + 16$

${\left(x + 3\right)}^{2} + {\left(y - 4\right)}^{2} = 25$