Question

How do you find the x-intercepts of a quadratic function in standard form given `f(x) = 2(x+1)^2 - 3`?

Answer 1

`x = - 1 +- sqrt6/2`

Explanation:

This function is written in vertex form.
To find the x-intercepts, make f(x) = 0.
`2(x + 1)^2 - 3 = 0`
`(x + 1)^2 = 3/2`
`x + 1 = +- sqrt3/sqrt2`
`x = - 1 +- sqrt3/sqrt2`, or
`x = - 1 +- sqrt6/2`