How do you solve #-10-5n^2=-330#?

2 Answers
Jun 12, 2017

Answer:

See a solution process below:

Explanation:

First, add #color(red)(10)# to each side of the equation to isolate the #n# term while keeping the equation balanced:

#color(red)(10) - 10 - 5n^2 = color(red)(10) - 330#

#0 - 5n^2 = -320#

#-5n^2 = -320#

Next, divide each side of the equation by #color(red)(-5)# to isolate #x^2# while keeping the equation balanced:

#(-5n^2)/color(red)(-5) = (-320)/color(red)(-5)#

#(color(red)(cancel(color(black)(-5)))n^2)/cancel(color(red)(-5)) = 64#

#n^2 = 64#

Now, take the square root of each side of the equation to solve for #n# while keeping the equation balanced. Remember, the square root of a number produces a positive and negative result:

#sqrt(n^2) = +-sqrt(64)#

#n = +-8#

Jun 13, 2017

Answer:

See below

Explanation:

#-10-5n^2=-330#

#320=5n^2#

#64=n^2#

#n=pm8#