# How do you solve -10-5n^2=-330?

Jun 12, 2017

See a solution process below:

#### Explanation:

First, add $\textcolor{red}{10}$ to each side of the equation to isolate the $n$ term while keeping the equation balanced:

$\textcolor{red}{10} - 10 - 5 {n}^{2} = \textcolor{red}{10} - 330$

$0 - 5 {n}^{2} = - 320$

$- 5 {n}^{2} = - 320$

Next, divide each side of the equation by $\textcolor{red}{- 5}$ to isolate ${x}^{2}$ while keeping the equation balanced:

$\frac{- 5 {n}^{2}}{\textcolor{red}{- 5}} = \frac{- 320}{\textcolor{red}{- 5}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{- 5}}} {n}^{2}}{\cancel{\textcolor{red}{- 5}}} = 64$

${n}^{2} = 64$

Now, take the square root of each side of the equation to solve for $n$ while keeping the equation balanced. Remember, the square root of a number produces a positive and negative result:

$\sqrt{{n}^{2}} = \pm \sqrt{64}$

$n = \pm 8$

Jun 13, 2017

See below

#### Explanation:

$- 10 - 5 {n}^{2} = - 330$

$320 = 5 {n}^{2}$

$64 = {n}^{2}$

$n = \pm 8$