How do you solve #2k^2-2=144#?

1 Answer
Aug 3, 2016

Answer:

#k = +-sqrt73 #

Explanation:

Notice that all the numbers are even. The first thing to do is to divide by 2.

#k^2-1=72#

Usually in a quadratic equation, we make it equal to 0, but this is an exception because there is no #x-#term. Change it to #x^2 = c#

#k^2 = 73#

#k = +-sqrt73 # Remember to take the positive and negative root.