# How do you solve 2k^2-2=144?

Aug 3, 2016

$k = \pm \sqrt{73}$

#### Explanation:

Notice that all the numbers are even. The first thing to do is to divide by 2.

${k}^{2} - 1 = 72$

Usually in a quadratic equation, we make it equal to 0, but this is an exception because there is no $x -$term. Change it to ${x}^{2} = c$

${k}^{2} = 73$

$k = \pm \sqrt{73}$ Remember to take the positive and negative root.