How do you solve #5(x-1)^2=50#?

1 Answer
Jul 4, 2017

Answer:

#x=1+-sqrt10#

Explanation:

#"divide both sides of the equation by 5"#

#5/5(x-1)^2=50/5#

#rArr(x-1)^2=10#

#color(blue)"take the square root of both sides"#

#sqrt((x-1)^2)=+-sqrt10larr" note plus or minus"#

#rArrx-1=+-sqrt10#

#"add 1 to both sides"#

#xcancel(-1)cancel(+1)=1+-sqrt10#

#rArrx=1+-sqrt10#