How do you solve the equation 2x^2+338=0?

May 8, 2017

$x = \pm 13 i$

Explanation:

First, we need to isolate $x$:

$2 {x}^{2} + 338 = 0$

subtract $338$ on both sides

$2 {x}^{2} = - 338$

divide by $2$

${x}^{2} = - 169$

take the square root of both sides

+-cancel(sqrt(x^cancel(2))$= \pm \sqrt{- 169}$

$x = \pm 13 i$

The $i$ comes from $\sqrt{- 1}$