# How do you find the vertex and intercepts for #y=-x^2+4x+12#?

##### 1 Answer

Jul 9, 2017

x-coordinate of vertex;

y-coordinate of vertex:

Vertex (2, 16)

Make x = 0 --> y-intercept = 12

Make y = 0, and solve the quadratic equation:

Find 2 real roots knowing the sum (b = 4) and product (ac = - 12). The 2 x-intercepts are: x = - 2 and x = 6.

graph{- x^2 + 4x + 12 [-40, 40, -20, 20]}