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1

Answer:

16

Explanation:

Method 1: Simplify the fraction and evaluate
#7+45/5#
#=7+9#
#=16#

Method 2: Convert to fractions and evaluate
#7+45/5#
#=35/5+45/5#
#=80/5#
#=16#

1

Answer:

#70#

Explanation:

When solving, you have to follow the order of operations.
Calculations are done from left to right, for convention.

However, you must always first work out the inside of the parenthesis.

Then,carry out the multiplication/division.
Lastly, carry out the addition/subtraction.

#8−2[5−(12−6)^2]#

#=8-2[5-(color(red)6)^2]#

#=8-2[5-color(red)(36)]#

#=8-2[color(red)(-31)]#

#=8-(color(red)(-62))#

#=70#

1

Answer:

#$3.33#

Explanation:

If five pencils cost #$1.85# then we can divide the total cost by #5# to determine the price of each pencil:

#1.85/5=0.37larr# This tells us the cost of one pencil

So if one pencil costs #$0.37#, then to find the cost of #9# pencils, we multiply this quantity by #9#

#:.0.37times9=3.33larr# The total cost in dollars

1

Answer:

-39 Use the order of operations and integers to solve.

Explanation:

The way the students of Carr Junior High in Santa Ana CA remember the order of operations is as follows.

If you get hurt in PE call an MD Asap ( call a doctor as soon as possible)

P states for parenthesis so do the work inside of the Parenthesis first.
E = exponents there are no exponents in this expression.

( 5+ 9 -1) ASap A = addition S = Subtraction. ( As soon as possible is one time not two, so do Addition and Subtraction at the same time working from left to right )

# 5+ 9 -1 = 14 -1#

# 14 -1 = 13#

so after removing the first parenthesis gives

# 13 xx ( -3) # MD is a doctor one person not two, so do multiplication and division at the same time working from left to right.

# 13 xx ( -3) = - 39 #

A positive times a negative is a negative.
a negative ( taking way) something good ( a positive) is bad ( negative)

2

Answer:

Convert to equivalent fractions with bigger denominators.

Explanation:

The easiest way to find fractions between given fractions is to convert to equivalent fractions with much bigger denominators,
then you can write down any number of fractions by inspection.

We have #1/3 and 2/3# which are equal to #color(blue)(10/30 and 20/30)#

Fractions between these two have numerators from #11 " to " 19#

#color(blue)(10/30), 11/30, 12/30, 13/30 ....... 17/30, 18/30, 19/30, color(blue)(20/30)" "larr# (some simplify)

#1/3 and 2/3# are also equal to #color(blue)(15/45 and 30/45)#

Between these we have fractions with numerators from #16 " to " 29#

#color(blue)(15/45), 16/45, 17/45, 18/45 ..........27/45, 28/45, 29/45,color(blue)(30/45)#

The bigger you choose the denominator, the more choices you have:
#1/3 and 2/3# are equal to #color(blue)(100/300 and 200/300)#

Fractions between these two have numerators from #101 " to " 199#

#color(blue)(100/300),101/300, 102/300, 103/300............197/300, 198/300, 199/300,color(blue)(200/300)#

ad infinitum ....

1

Answer:

The equivalent fractions below all simplify to #3/5#

Explanation:

Equivalent fractions are those which have the same size, but they look different because they have different numerators and denominators. However, they all simplify to the same fraction in simplest form.

You can find equivalent fractions by multiplying the top and bottom by the same number.

#9/15 xx 2/2 = 18/30#

#9/15 xx 5/5 = 45/75#

#9/15 xx 10/10 = 90/150#

#9/15 xx11/11 = 99/165#

#9/15 div 3/3 = 3/5#

#9/10 xx (2/3)/(2/3) = 6/10#

1

Answer:

See below

Explanation:

#(km)/h#

We want meters to be in the denominator, so we'll use the following conversion factor to get to #m/h#:

#((km)/h)((1000 m)/(1km))=(1000m)/h#

To get seconds in the denominator, we'll use the following conversion factor:

#((km)/h)((1000 m)/(1km))((1h)/(60s))=(1000m)/(60s)#

#(1000m)/(60s)# is conversion factor you would use to convert #(km)/h# to #m/s#.

2

Answer:

The answer to #55+57+58+61+63# is #294# and further explanation in down below!

Explanation:

The way we are going to evaluate this problem is going to be like, add first 2 numbers and add the answer to that to the next number and so on. Kind of like a pattern! I hope that makes sense, but if it doesn't, I hope you'll get it soon! :)

OK, now let's start!

#55+57= 112#

Now add #112# to the next number in the equation. Like,

#112+58= 170#!

You keep doing that till you are finished with all of your numbers!

#170+61= 231#

#231+63= 294#

There you go! The answer is 294 and I hope that you know understood the "pattern" that I used instead of adding all of them together at the same time! I hope that this answer helps you! :)
My source is my mind!

1

Answer:

#85/12# or #7 1/12#

Explanation:

1. Convert #5 1/3# into an improper fraction. Multiply 5 by 3, then add 1 to get the numerator. 3 remains the denominator.

#5 1/3 = 16/3#

2. We need to get a least common denominator (LCD) for all three fractions.

Multiples of 4: 4, 8, 12...
Multiples of 3: 3, 6, 9, 12...
Multiples of 2: 2, 4, 6, 8, 10, 12...

The smallest number that can be divided by 4, 2, and 3 is 12.

3. Multiply each fraction in the expression by a equivalent form of 1 so that each has a denominator of 12.

#(1/4)(3/3) + (3/2)(6/6) + (16/3)(4/4)#
#= (3/12) + (18/12) + (64/12)#

4. Add the fractions. Remember, when adding fractions, only add the numerators together and keep the denominators the same.

# = 85/12#

Since #(85/12)# is in simplest form, you could keep your answer as an improper fraction . You could also convert it into a mixed fraction, which would be #7 1/12#. (12 goes into 85 seven times, with a remainder of 1.)

1

Answer:

#105#

Explanation:

Apply the following rule: #a/(b/c)=atimesc/b#

#:.42/(2/5)->42*5/2=210/2=105#