Featured 3 weeks ago

The least common multiple (LCM) of

I always take the first 5 multiples of each number and write them down. And if we don't our LCM in there, then I write down the next five multiples! So let's start, shall we?

**(First 5) Multiples of #6#**:

**(First 5) Multiples of #9#**:

Now, we have to see if there is any common number in the numbers. If we do, we have to make sure that there isn't any other number *lower* than that that

**(First 5) Multiples of #6#**:

**(First 5) Multiples of #9#**:

There isn't any number before *both* go into, so

Source: My knowledge!

I hope that helps you!

Featured 3 weeks ago

See a solution process below:

We can rewrite this as:

To multiply the numbers on the right we combine the number of

Featured 3 weeks ago

Alternatively, using scientific notation makes things easier (even though it's technically the same method).

The answer is

Therefore:

#1 xx 10^color(red)9 xx 6 xx 10^color(red)9#

#= (1 xx 6) xx (10^color(red)9 xx 10^color(red)9)#

#= 6 xx 10^(color(red)9 + color(red)9)#

#= 6 xx 10^color(blue)18#

#= 6,underbrace(000,000,000,000,000,000)_(color(blue)"18 ""zeros")#

*Final Answer*

Featured 1 week ago

Divide both the numerator and the denominator by

Featured 1 week ago

To list the prime numbers between

All even numbers are divisible 2, they are not prime. apart from

This leaves all the odd numbers.

A number ending in

If the sum of the digits is divisible by

As factors are always in pairs we only need to consider factors less than the square roots.

Featured 1 week ago

See a solution process below:

First, evaluate the expression within the right parenthesis:

Next, rewrite both terms within parenthesis. Remember, minus a minus is a plus:

Now, evaluate the addition operations left to right:

Featured 5 days ago

=

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Featured 5 days ago

Use the laws of indices.

It helps to know the powers less than 1000 by heart.

Featured 5 days ago

In order to solve this, we will use dimensional analysis.

First, to eliminate the

#("156" cancel("mi")) / "4 hr" * color(blue)("5280 ft" / ("1" cancel("mi")))#

Now, we are left with

#("156" cancel("mi")) / ("4" cancel("hr")) * "5280 ft" / ("1" cancel("mi")) * color(blue)(("1" cancel("hr")) / "60 min")# #-># cancels out the#"hr"# unit

#("156" cancel("mi")) / ("4" cancel("hr")) * "5280 ft" / ("1" cancel("mi")) * ("1" cancel("hr")) / ("60" cancel("min")) * color(blue)(("1" cancel("min"))/ "60 s")# #-># cancels out the#"min"# unit

Now, we are left with our desired unit of

#(156 * "5280 ft") / (4 * 60 * "60 s") = "57.2 ft/s"#

So,

Featured 4 days ago

By 'unit rate', we mean how many of the first quantity for ONE of the second unit.

So, by 'feet per second, we mean, how many feet are covered in ONE second?

We can convert the given quantities to the required units:

miles

hours