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#"sum the parts of the ratio"#

#rArr6+5+7=18#

#"the sum of the angles in a triangle "=180^@#

#rArr180^@/18=10^@larrcolor(blue)"1 part of the ratio"#

#rArr6" parts "=6xx10^@=60^@#

#rArr5" parts "=5xx10^@=50^@#

#rArr7" parts "=7xx10^@=70^@#

#"the 3 angles are "60^@,50^@" and "70^@#

Featured yesterday

See below.

Here we are formulating an equation to solve for

We know that the interior angles of any triangle adds up

We have three angles given:

This means that :

Now we collect like terms to simplify.

Now we solve like any linear equation by isolating the variable on one side of the equation with the constant on the other.

Here we must subtract **both** sides to isolate the

We want one

Here we divide by

We can check if we are right by putting our value of

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Triangle sum theorem states that all angles in a triangle must add up to

You have already applied the triangle sum theorem which states that all 3 angles in a triangle add up to

So

The angle

Featured 15 hours ago

Longest possible perimeter of the triangle is

To find the longest possible perimeter of the triangle.

Third angle

To get the longest perimeter, smallest angle

Using sine law,

Longest possible perimeter of the triangle is

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Perimeter of isosceles triangle

To find the longest possible perimeter of the triangle.

Third angle

It’s an isosceles triangle with

Least angle

Applying sine law,

Perimeter of isosceles triangle

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Three angles are in the ratio

In a triangle sum of the three angles =

Let basic unit x be the unit of each angle.

Then,

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No. Of spheres that the cylinder can contain = **6**.

Water overflowing volume = **678.54cc**

Volume of cylinder

Given :

Volume of sphere

Given

No. of spheres that can be placed in the cylinder

Water that will be overflowing after dropping 6 spheres in it = 6 * 113.09 = 678.54# cc

Featured yesterday

#"sum the parts of the ratio "#

#rArr4+3+2=9" parts"#

#• " the sum of the 3 angles in a triangle "=180^@#

#rArr180^@/9=20^@larrcolor(blue)"1 part"#

#rArr4" parts "=4xx20^@=80^@#

#rArr3" parts "=3xx20^@=60^@#

#rArr2" parts "=2xx20^@=40^@#

#"the 3 angles in the triangle are"#

#80^@,60^@" and "40^@#

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9)

10)

11)

12)

9)

10)

11)

12)

Featured 15 hours ago

#"the volume (V) of a cone is calculated using "#

#•color(white)(x)V=1/3pir^2h#

#"where r is the radius of the base and h the height"#

#"we require to find r the radius"#

#"using the formula for the circumference (C) of a circle"#

#•color(white)(x)C=2pir#

#rArr2xx3.14xxr=56.52#

#rArr6.28r=56.52#

#"divide both sides by "6.28#

#(cancel(6.28) r)/cancel(6.28)=56.52/6.28rArrr=9#

#rArrV=(3.14xx81xx5)/3~~423.9toD#