Question #5f9ca

Joëlle
Joëlle
8.408219178082192 years ago · Biology

Answer:

Red blood cells have lost their nucleus prior to reaching the circulation. Several mechanisms have been proposed.

Explanation:

This is quite a long answer, because a lot is still unknown. I've tried to make it as complete and understandable as possible.

Mature erythrocytes develop from stem cells in bone marrow in several steps as shown in the image below. A proerythroblast with a nucleus develops to a reticulocyte without nucleus in about 7 days. A reticulocyte is formed after enucleation ('loss' of the nucleus) in the step before. Reticulocytes can enter the blood stream and mature there in 1 to 2 day into erythrocytes. So a red blood cell as we know it already lost its nucleus.

http://nephrotube-anemia-ckd.blogspot.nl/p/erythropoiesis-rbcs-formation.html

Changes in the early maturation process involve condensation of chromosomes and suppression of transcription. Also the scaffolds in the cell (microfilaments) are partially degraded, making the cell more flexible.

Apoptosis
One theory about how enucleation is carried out includes apoptosis (programmed cell death). This is supported by findings that part of the genetic material is degraded and that part of the nuclear material leaks into the cytoplasm prior to enucleation. Although it might be a part of the mechanism, studies show that enucleation can occur without apoptosis.

Asymmetric cytokinesis
Another theory is that enucleation is a form of asymmetric cytokinesis: the contents of the cell are unequally divided between the two daughter cells. Since microfilaments are partly broken down, the nucleus can move to one side of the cell (polarization). Two cells are created:

  1. reticulocyte: cell with most of the cytoplasm but without the nucleus; destined to become a mature erythrocyte
  2. pyrenocyte: cell with the nucleus and a small amount of cytoplasm; destined to be degraded.

The fact that pyrenocytes do contain some plasma and have a cellular membrane shows that the nucleus isn’t simply expelled, but neatly packaged.

Involvement of macrophages
Macrophages appear to be involved in the process of nuclear extrusion and probably degrade the pyrenocytes. Studies showed that pyrenocytes have different membrane proteins/ phospholipids than reticulocytes, which might explain why macrophages selectively bind to the pyreneocytes.

As with the apoptosis theory, it has been shown that enucleation can also occur without macrophages, meaning there are other processes involved.

Outlook
Much research is spent now on finding the factors that trigger enucleation and to clarify the exact mechanims. Being able to understand this process is important because it would give researchers the tools to make blood for transfusion from stem cells. In addition, enucleation has been proposed as a good way to kill cancer cells.

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Question #5f9ca

Joëlle
Joëlle
8.408219178082192 years ago · Biology

Answer:

Red blood cells have lost their nucleus prior to reaching the circulation. Several mechanisms have been proposed.

Explanation:

This is quite a long answer, because a lot is still unknown. I've tried to make it as complete and understandable as possible.

Mature erythrocytes develop from stem cells in bone marrow in several steps as shown in the image below. A proerythroblast with a nucleus develops to a reticulocyte without nucleus in about 7 days. A reticulocyte is formed after enucleation ('loss' of the nucleus) in the step before. Reticulocytes can enter the blood stream and mature there in 1 to 2 day into erythrocytes. So a red blood cell as we know it already lost its nucleus.

http://nephrotube-anemia-ckd.blogspot.nl/p/erythropoiesis-rbcs-formation.html

Changes in the early maturation process involve condensation of chromosomes and suppression of transcription. Also the scaffolds in the cell (microfilaments) are partially degraded, making the cell more flexible.

Apoptosis
One theory about how enucleation is carried out includes apoptosis (programmed cell death). This is supported by findings that part of the genetic material is degraded and that part of the nuclear material leaks into the cytoplasm prior to enucleation. Although it might be a part of the mechanism, studies show that enucleation can occur without apoptosis.

Asymmetric cytokinesis
Another theory is that enucleation is a form of asymmetric cytokinesis: the contents of the cell are unequally divided between the two daughter cells. Since microfilaments are partly broken down, the nucleus can move to one side of the cell (polarization). Two cells are created:

  1. reticulocyte: cell with most of the cytoplasm but without the nucleus; destined to become a mature erythrocyte
  2. pyrenocyte: cell with the nucleus and a small amount of cytoplasm; destined to be degraded.

The fact that pyrenocytes do contain some plasma and have a cellular membrane shows that the nucleus isn’t simply expelled, but neatly packaged.

Involvement of macrophages
Macrophages appear to be involved in the process of nuclear extrusion and probably degrade the pyrenocytes. Studies showed that pyrenocytes have different membrane proteins/ phospholipids than reticulocytes, which might explain why macrophages selectively bind to the pyreneocytes.

As with the apoptosis theory, it has been shown that enucleation can also occur without macrophages, meaning there are other processes involved.

Outlook
Much research is spent now on finding the factors that trigger enucleation and to clarify the exact mechanims. Being able to understand this process is important because it would give researchers the tools to make blood for transfusion from stem cells. In addition, enucleation has been proposed as a good way to kill cancer cells.

Answer:

It is #900^{\circ}/7#

Explanation:

From #alpha^{\circ}/alpha=360^{\circ}/(2*pi)# we get
#alpha^{\circ}=180^{\circ}/pi*5/7*pi#
canceling the #pi# we get
#alpha^{\circ}=900^{\circ}/7#

Answer:

#color(maroon)("Total Surface Area " = color(purple)(A_T = A_B + A_L = color(crimson)(15.45 + 94.12 = 109.57#

Explanation:

https://socratic.org/questions/a-pyramid-has-a-parallelogram-shaped-base-and-a-peak-directly-above-its-center-i-95

#l = 8, b = 2, theta = (5pi)/12, h = 9#

#"To find the Total Surface Area T S A"#

#"Area of parallelogram base " A_B = l b sin theta#

#A_B = 8 * 2 * sin ((5pi)/12) = 15.45#

#S_1 = sqrt(h^2 + (b/2)^2) = sqrt(9^2 + 1^2) = 9.06#

#S_2 = sqrt(h^2 + (l/2)^2) = sqrt(9^2 + 4^2) = 10.82#

#"Lateral Surface Area " A_L = 2 * ((1/2) l * S_1 + (1/2) b * S_2#

#A_L = (cancel2 * cancel(1/2)) * (l * S_1 + b * S_2) = (8 * 9.06 + 2 * 10.82)#

#A_L = 94.12#

#"Total Surface Area " A_T = A_B + A_L = 15.45 + 94.12 = 109.57#

Question #f71f9

maxxal22
maxxal22
Featured 7.093150684931507 years ago · Biology

Answer:

p= 0.6001
q= 0.399
#p^2#= pp = 235.864 --> 236
pq= 313.177 --> 313
#q^2#=qq=103.958 --> 104

Explanation:

We know that our Population X is 653 individuals. Of this population 104 have floppy ears (Xf). We know that p (short) is dominant over q (floppy).

Basic equations for Hardy Weinberg:
#p^2# + 2pq + #q^2# = 1
p + q = 1

#q^2# is the same as the # X / (Xf)# . solving this gives 0.15926
Taking the square root of this number gives us the frequency
q= 0.399

Now we can enter this into p+q=1
This means that p= 1 - q which solves to 0.6001

Now that we now both p and q we can start calculating the frequencies of the genotypes
#p^2# for type pp gives 0.6001 * 0.6001 = 235.864 Round this number up to 236

2pq gives 2 * 0.6001 * 0.399 = 313.177 which gets rounded up to 313

#q^2# for type qq gives 0.399 * 0.399= 103.958 which gets rounded up tp 104

To find the frequency of each genotype we divide the total population by each genotypes' population.
fpp = #236/653#= 0.367140....
fpq = #313/653#= 0.47932....
fqq= #104/653#=0.15926.....

Answer:

The quick answer is that “Like dissolves like”.

Explanation:

Why is this so?

Polar substances tend to dissolve in polar solvents, and nonpolar substances dissolve in nonpolar solvents.

When a solute dissolves in a solvent the individual particles of the solute separate from their neighbours and move between the spaces of the solvent particles.

The solvent particles collide with the solute particles and the intermolecular forces of attraction between solute and solvent particles "hold" the solute particles in the spaces.

There are three steps to the dissolving process:

  1. The solvent particles must move apart to make room for solute particles. This process requires energy to overcome forces of attraction between solvent particles. This step is endothermic.

  2. The solute particles must separate from their neighbours. This process also requires energy to overcome the forces of attraction between the solute particles. This step is endothermic.

  3. When the solute particles move between the solvent particles, the intermolecular forces of attraction between solute and solvent take hold and the particles "snap" back and move closer. This process releases energy. This final step is exothermic.

Consider the process of dissolving a crystal of salt (#"NaCl"#) in water.

nutrition.jbpub.com

A sodium crystal consists of an array of sodium ions (yellow) and chloride ions (green).

Water is a polar solvent: the #"O"# end has a partial negative (#δ^-#) charge, and the #"H"# ends have #δ^+# charges.

When you put the salt in water, the #δ^+# ends of the water molecules surround the #"Cl"^-# ions from the #"NaCl"#, and the #δ^-# ends of the water surround the #"Na"^+# ions of the #"NaCl"#.

The ions become solvated (hydrated).

This is an energy-releasing process.

Then, the positive and negative ends of the #"H"_2"O"# that are not surrounding the #"NaCl"# ions attract each other, holding everything together in a three dimensional H-bonding network.

The #"NaCl"# dissolves because you get back more energy from hydration of the #"Na"^+# and #"Cl"^-# ions than it takes to remove the ions from the surface of the crystal.

What if you have a polar liquid such as ethanol, #"C"_2"H"_5"OH"#?

Will it dissolve in water?

The molecules of ethanol are attracted to each other by H-bonding.

And the molecules of water are attracted to each other by H-bonding.

If you gently add ethanol to water, you may get two layers, in which the less dense ethanol is on the top.

solubilityinwater.files.wordpress.com

At the interface between the layers, the ethanol molecules can H-bond to the water, and the water molecules can H-bond to the ethanol.

Because the attractions between the molecules are similar, the molecules can mix freely with each other.

Water and ethanol are miscible in all proportions.

All it takes is a gentle swirl, and we have a homogeneous mixture (a solution) of the two substances.

What if you have a nonpolar substance such as hexane?

Will it dissolve in water?

If we add hexane to water, the hexane will float on the top of the water with no apparent mixing.

www.mpcfaculty.net

The attractive forces among the hexane molecules are the relatively weak London dispersion forces.

The attractive forces among the water molecules are the relatively strong H-bonds.

The only attractive forces among the hexane and water molecules are London forces.

Thus, a few hexane molecules will enter the water layer, but the strong attractive forces among the water molecules keeps most of the hexane molecules out.

Similarly, a few water molecules will enter the hexane layer because of the water-hexane London forces.

Water and hexane are immiscible. They do not dissolve in each other.

Finally, will nonpolar substances such as hexane and pentane dissolve in each other?

The attractive forces among both the hexane and the pentane molecules are the relatively weak London dispersion forces.

There is little resistance to a molecule of one compound moving into the other layer.

When the nonpolar pentane molecules move into the nonpolar hexane, London forces are disrupted between the hexane molecules, but new London forces are formed between hexane and pentane molecules.

Because the molecules are so similar, the structure of the solution and the strengths of the attractions between the particles are very similar to the structure and attractions found in the separate liquids.

When these properties are not significantly different in the solution than in the separate liquids, it is largely the natural tendency of a system towards increased disorder (greater entropy) that drives them into solution.

Thus, polarity affects solubility.

If solute and solvent have approximately the same polarity, they will probably form a solution.

“Like dissolves like”: Polar solutes dissolve in polar solvents; nonpolar solutes dissolve in nonpolar solvents.

Answer:

The five major branches of chemistry are organic, inorganic, analytical, physical, and biochemistry. These divide into many sub-branches.

Explanation:

ORGANIC CHEMISTRY

Organic chemistry involves the study of the structure, properties, and preparation of chemical compounds that consist primarily of carbon and hydrogen.

Organic chemistry overlaps with many areas including

  • Medicinal chemistry —the design, development, and synthesis of medicinal drugs. It overlaps with pharmacology (the study of drug action).
  • Organometallic chemistry — the study of chemical compounds containing bonds between carbon and a metal.
  • Polymer chemistry — the study of the chemistry of polymers.
  • Physical organic chemistry — the study of the interrelationships between structure and reactivity in organic molecules.
  • Stereochemistry — the study of the spatial arrangements of atoms in molecules and their effects on the chemical and physical properties of substances.

INORGANIC CHEMISTRY

Inorganic chemistry is the study of the properties and behaviour of inorganic compounds.

It covers all chemical compounds except organic compounds.

Inorganic chemists study things such as crystal structures, minerals, metals, catalysts, and most elements in the Periodic Table.

Branches of inorganic chemistry include:

  • Bioinorganic chemistry — the study of the interaction of metal ions with living tissue, mainly through their direct effect on enzyme activity.

  • Geochemistry — the study of the chemical composition and changes in rocks, minerals, and atmosphere of the earth or a celestial body.

  • Nuclear chemistry — the study of radioactive substances.

  • Organometallic chemistry — the study of chemical compounds containing bonds between carbon and a metal.

  • Solid-state chemistry — the study of the synthesis, structure, and properties of solid materials.

ANALYTICAL CHEMISTRY

Analytical chemistry involves the qualitative and quantitative determination of the chemical components of substances.

Examples of areas using analytical chemistry include:

  • Forensic chemistry — the application of chemical principles, techniques, and methods to the investigation of crime.

  • Environmental chemistry —the study of the chemical and biochemical phenomena that occur in the environment.It relies heavily on analytical chemistry and includes atmospheric, aquatic, and soil chemistry.

  • Bioanalytical Chemistry — the examination of biological materials such as blood, urine, hair, saliva, and sweat to detect the presence of specific drugs.

PHYSICAL CHEMISTRY

Physical Chemistry —the study of the effect of chemical structure on the physical properties of a substance.

Physical chemists typically study the rate of a chemical reaction, the interaction of molecules with radiation, and the calculation of structures and properties.

Sub-branches of physical chemistry include:

  • Photochemistry — the study of the chemical changes caused by light.

  • Surface chemistry — the study of chemical reactions at surfaces of substances. It includes topics like adsorption, heterogeneous catalysis, formation of colloids, corrosion, electrode processes, and chromatography.

  • Chemical kinetics — the study of the rates of chemical reactions, the factors affecting those rates, and the mechanism by which the reactions proceed.

  • Quantum chemistry — the mathematical description of the motion and interaction of subatomic particles. It incorporates quantization of energy, wave-particle duality, the uncertainty principle, and their relationship to chemical processes.

  • Spectroscopy — the use of the absorption, emission, or scattering of electromagnetic radiation by matter to study the matter or the chemical processes it undergoes.

BIOCHEMISTRY

Biochemistry is the study of chemical reactions that take place in living things. It tries to explain them in chemical terms.

Biochemical research includes cancer and stem cell biology, infectious disease, and cell membrane and structural biology.

It spans molecular biology, genetics, biochemical pharmacology, clinical biochemistry, and agricultural biochemistry.

  • Molecular biology — the study of the interactions between the various systems of a cell, such as the different types of DNA, RNA, and protein biosynthesis.

  • Genetics — the study of genes, heredity, and variation in living organisms.

  • Pharmacology — the study of mechanisms of drug action and the influence of drugs on an organism.
    o Toxicology —a sub-branch of pharmacology that studies the effects of poisons on living organisms.

  • Clinical biochemistry — the study of the changes that disease causes in the chemical composition and biochemical processes of the body.

  • Agricultural biochemistry — the study of the chemistry that occurs in plants, animals, and microorganisms.

Thus, although there are FIVE main branches of chemistry, there are many sub-branches.

There is a huge overlap between Chemistry and Biology, Medicine, Physics, Geology, and many other disciplines.

Chemistry really is THE CENTRAL SCIENCE.

Question #f2711

Ernest Z.
Ernest Z.
10.805479452054794 years ago · Chemistry

Answer:

The wavelength decreases as the frequency increases.

Explanation:

The wavelength #λ# is the distance between successive peaks in a wave.

The frequency #f# of a wave is the number of complete waves that pass a point in a given time.

resource.isvr.soton.ac.uk

Above we see two sound waves travelling through space at the same velocity #v#.

The red dot follows the amplitude of the wave as it goes by.

The frequency of oscillation of the dot is the frequency #f# of the wave. The second wave has twice the frequency of the first.

You can see that the wavelength is halved when the frequency is doubled.

The frequency #f# and wavelength #λ# are related to one another and to the speed of the wave #v# by the formula

#fλ = v#.

Since #v# is constant, if #f# increases, #λ# must decrease, and vice versa.

Answer:

The overall (unbalanced) chemical equation for cellular respiration is:

#"C"_6"H"_12"O"_6 + "O"_2 → "CO"_2 + "H"_2"O" + "energy"#

Explanation:

The balanced equation is

#"C"_6"H"_12"O"_6 + "6O"_2 → "6CO"_2 + "6H"_2"O" + "energy"#

The equation expressed in words would be:

#"glucose + oxygen → carbon dioxide + water + energy"#

The equation is formulated by combining the three following processes into one equation:

  1. Glycolysis — the breakdown of the form of a glucose molecule into two three-carbon molecules i.e. pyruvate (pyruvic acid).

  2. The Tricarboxylic Acid Cycle or Krebs Cycle — the three-carbon pieces are pulled apart bit by bit to release the energy stored in those covalent bonds. This is where most of the #"CO"_2# is formed.

  3. The Electron Transport Chain and Oxidative Phosphorylation — this sequence requires the #"O"_2# and produces most of the energy. This energy comes in the form of #"ATP"#, or adenine triphosphate.

Answer:

You divide the final volume by the initial volume.

Explanation:

#"DF" = V_f/V_i#

EXAMPLE 1:

What is the dilution factor if you add a 0.1 mL aliquot of a specimen to 9.9 mL of diluent?

Solution:

#V_f = "aliquot volume + diluent volume" = "(0.1 + 9.9) mL" = "10.0 mL"#

#"DF" = V_f/V_i = (10.0 cancel("mL"))/(0.1cancel("mL")) = 100#

You have diluted the sample by a factor of 100.

The dilution factor is often used as the denominator of a fraction.

For example, a #"DF"# of 100 means a 1:100 dilution.

EXAMPLE 2:

How would you make 500 mL of a 1:250 dilution?

Solution:

#"DF" = V_f/V_i#

#V_i = V_f/("DF") ="500 mL"/250 = "2.00 mL"#

Pipet 2.00 mL of your stock solution into a 500 mL volumetric flask.

Add diluent to the mark on the flask (you will have added about 498 mL of water).

You now have a 1:250 dilution of your original solution.

Answer:

The maximum density of water occurs at 4 °C because, at this temperature two opposing effects are in balance.

Explanation:

In ice, the water molecules are in a crystal lattice that has a lot of empty space.

wps.prenhall.com

When the ice melts to liquid water, the structure collapses and the density of the liquid increases.

At temperatures well above freezing, the molecules move faster and get further apart. The density decreases as temperature increases.

At temperatures near 0 °C, the water still contains many ice-like clusters. These clusters are free to move relative to each other, so water is still liquid.

The clusters still have empty spaces, so they decrease the density of the liquid.

The molecules of the water are closer together, and this increases the density of the liquid.

Now, let's cool the water.

As the temperature of warm water decreases, the water molecules slow down and the density increases.

At 4 °C, the clusters start forming.

The molecules are still slowing down and coming closer together, but the formation of clusters makes the molecules be further apart.

Cluster formation is the bigger effect, so the density starts to decrease.

Thus, the density of water is a maximum at 4 °C.

hyperphysics.phy-astr.gsu.edu

What is dna?

Anthony F.
Anthony F.
10.438356164383562 years ago · Biology

Answer:

Deoxyribonucleic Acid is the meaning of it. It is a nucleic acid that is the carrier of genetic information.

Explanation:

DNA are the letters of deoxyribonucleic acid.

All life on earth uses this nucleic acid as the genetic code.

A nucleic acid is a polynucleotide. A polynucleotide consists of three basic units: a phosphate group, a 5 carbon sugar (pentose), and a nitrogenous base. The five carbon sugar is deoxyribose. Since a polynucleotide chain, the phosphate and deoxyribose units are repetitive, the variation is provided by the nitrogenous bases.

There are four bases: adenine, guanine, cytosine, and thymine.
Both adenine and guanine are purines which have a double ring structure. Cytosine and thymine are pyramidines which consist of a single ring structure.

The DNA molecule is double helix, a spiral shaped ladder. The upright or backbone of the ladder is made of alternating pentose and phosphate groups held together by covalent bonds. The rungs or steps of the ladder consist of the bases. These bases are joined to the pentose sugars with covalent bonds. Adenine pairs with thymine using two hydrogen bonds and cytosine pairs with guanine using three hydrogen.

https://ghr.nlm.nih.gov/handbook/basics/dna

The genetic code is determined by the linear sequence of the bases.

For example the sequence of adenine guanine thymine does not carry the same message as guanine thymine adenine.

The code is arranged in triplet form which codes for RNA which in turn codes for amino acids which form the basis of proteins.